assume toPosition is opposite to fromPosition
This commit is contained in:
@@ -82,8 +82,6 @@ export default ({
|
||||
targetY: number,
|
||||
targetPosition: Position | undefined;
|
||||
|
||||
let toCurvature: 'sourceCurvature' | 'targetCurvature';
|
||||
|
||||
switch (connectionHandleType) {
|
||||
case 'source':
|
||||
{
|
||||
@@ -93,7 +91,6 @@ export default ({
|
||||
targetX = toX;
|
||||
targetY = toY;
|
||||
targetPosition = toPosition;
|
||||
toCurvature = 'targetCurvature';
|
||||
}
|
||||
break;
|
||||
case 'target':
|
||||
@@ -104,7 +101,6 @@ export default ({
|
||||
targetX = fromX;
|
||||
targetY = fromY;
|
||||
targetPosition = fromPosition;
|
||||
toCurvature = 'sourceCurvature';
|
||||
}
|
||||
break;
|
||||
}
|
||||
@@ -143,10 +139,8 @@ export default ({
|
||||
};
|
||||
|
||||
if (connectionLineType === ConnectionLineType.Bezier) {
|
||||
// we don't know the destination position, so we can zero the to curvature
|
||||
dAttr = getBezierPath({ ...pathParams, [toCurvature]: 0 });
|
||||
// or we assume the destination position is opposite to the source position
|
||||
// dAttr = getBezierPath(pathParams);
|
||||
// we assume the destination position is opposite to the source position
|
||||
dAttr = getBezierPath(pathParams);
|
||||
} else if (connectionLineType === ConnectionLineType.Step) {
|
||||
dAttr = getSmoothStepPath({
|
||||
...pathParams,
|
||||
|
||||
Reference in New Issue
Block a user